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Contents:
Click Here for
the Telescope Calculator
Click Here for the Eyepiece Selection, Magnification,
Field of View & Exit Pupil Calculator
Aperture, Focal Length & Focal Ratio Magnification
Telescope Field of View
Minimum Magnification
Maximum Magnification
Resolution
First of all some definitions:
Aperture
The diameter of the main lens in a refractor or the main mirror in
a reflecting telescope. Measured in millimetres, centimetres,
metres, inches etc.
Use the letter “D” to represent the aperture.
Focal Length
This is the distance from the front surface of the mirror (or from
the plane of the lens for a refractor) at which an imaginary
parallel beam of light would be brought to a focus.
Use the symbol “F” to represent the focal
length.
Focal Ratio Use
the symbol “f” to represent focal ratio.
The focal ratio is calculated by
dividing the focal length (F) by the aperture (D).
So f
= F / D (Equation 1)
and F =
f x D (Equation 2)
A few examples :
A Mirror has an aperture
(D) of 200 mm.
It has a focal ratio (f) of 6.
What is the focal length (F)?
From Equation (2) above;
F
= f x D
= 6 x 200
= 1,200 mm is the focal length.
A Mirror has an aperture
(D) of 250 mm.
It has a focal length (F) of 1,250 mm.
What is the focal ratio (f)?
From Equation (1) above :
f
= F / D
= 1,250 / 250
= 5.0 is the focal ratio.
You may have heard the terms short
and long focal ratio. The former means that
“f” is a small number and the light is focussed in a relatively
short distance compared with the aperture of the mirror.
This makes for a compact telescope. But it is more difficult to
manufacture the mirror precisely, and the short focal ratio
causes increased off-axis aberrations (distortions) to the images,
particularly coma. Such aberrations mean that while objects at
the centre of the field of view will be focussed, nearer
the perimeter of the field of view, point sources (star images)
will be distorted.
The alternative long focal ratio
telescope brings the light gradually to a focus over a distance
which is many times the aperture of the main mirror. This
type of telescope is relatively long and bulky, but the mirror is
easier to manufacture and the aberrations such as coma, relatively
smaller.
Magnification
So how do we calculate the magnification
of a telescope?
Another piece of information is required, the
eyepiece focal length which we will call “e”.
When you inspect an eyepiece, the eyepiece
focal length will always be stamped somewhere usually upon the
bezel. The focal length is usually in millimetres, but some may
be in inches.
The magnification of the telescope (M)
is simply given by :
M = F /
e (F and e in the same units)
So for our 200 mm aperture telescope of
f/6 focal ratio with a focal length of 1,200 mm, an
eyepiece with a 25 mm eyepiece focal length (e) would give
a magnification of :
M
= 1,200 / 25
= x48 (meaning times 48
magnifications).
Similarly the same telescope with an eyepiece
with a 9 mm eyepiece focal length (e) would give a
magnification of :
M = 1,200 / 9
= x133.3
Telescope Field of View
How is the telescope
field of view calculated? Some more information is required.
Eyepieces are not
created equal. They are given names such as Kellner, Nagler,
Plossl, Erfle or more generic names such as Super Wide Angle.
There are three basic
facts to know about any eyepiece, the eyepiece focal length
(e), the diameter of the barrel (so it fits the diameter of your
focusser), and the eyepiece field of view sometimes known
as the effective field of view.
The eyepiece field
of view is the theoretical field of view in degrees the
eyepiece would provide at a magnification of one. Of
course such a low magnification can neither be achieved or
used in practice. Alternatively, the eyepiece field of view
can be thought of as the magnification required to give a
telescope field of view of one degree (about twice the
angular diameter of the full Moon).
The eyepiece field
of view varies with the type of eyepiece. The actual
telescope field of view is calculated by dividing the
eyepiece field of view by the magnification. So
Kellners have an eyepiece field of view of about 40
degrees. This means that at 40 magnifications a Kellner eyepiece
will give a 1 degree telescope field of view no matter what
the aperture of the mirror or the focal length or
focal ratio of the telescope.
Alternatively most
Plossl eyepieces will have an eyepiece field of view of
about 52 degrees. So at 52 magnifications, this eyepiece would
also give a 1 degree telescope field of view and at 40
magnifications would give a telescope field of view of
52/40 = 1.3 degrees.
Consider our example
telescope with a 200 mm f/6 mirror with a focal length of
1,200 mm. Consider using various eyepieces of 25 mm focal
length. Whatever the eyepiece type, you now know the
magnification will always be 1,200 / 25 or x48.
For a Kellner eyepiece
Eyepiece
field of view = 40°
Telescope
field of view = Eyepiece field of view /
Magnification
= 40/48
= 0.83
degrees
= 50.0
minutes of arc
For a Plossl eyepiece
Eyepiece
field of view = 52°
Telescope
field of view = Eyepiece field of view /
Magnification
= 52/48
= 1.08
degrees
= 65.0
minutes of arc
So for our 200 mm f/6 telescope, a 25 mm
Kellner eyepiece would show a patch of sky about 1.66 times the
diameter of the full Moon at a magnification of x48.
The 25 mm Plossl eyepiece would show a patch of
sky about 2.17 times the diameter of the full Moon at the same
magnification!
Minimum Magnification
There is a minimum recommended magnification
for each telescope, because of the size of the image formed by the
eyepiece (known as the exit pupil) and its relation to the
diameter of the pupil of the eye.
The iris is only fully open when the eye is
dark adapted. In young people a fully dark adapted eye has a
pupil diameter of about 7mm. This value decreases if there is any
stray light about, or with age. In the latter circumstances, the
maximum pupil diameter may only be 5 or 6 mm (or lower).
If the exit pupil is greater than 7mm,
the telescope is effectively wasting light because it cannot enter
the eye. This is critical if you are observing faint objects or
faint detail.
How can the diameter of the exit pupil
be calculated? Again (luckily) it is a simple calculation.
Exit Pupil of
Telescopic Image = Aperture / Magnification
<7
So for each telescope aperture, there is
a minimum magnification based on the exit pupil
diameter formed. Note that the exit pupil diameter is
independent of the eyepiece field of view discussed above.
|
Minimum Magnification |
|
Mirror Aperture (mm) |
Exit Pupil Diameter (mm) |
|
7 mm |
6 mm |
5 mm |
|
150 |
x22 |
x25 |
x30 |
|
200 |
x29 |
x33 |
x40 |
|
250 |
x36 |
x42 |
x50 |
|
300 |
x43 |
x50 |
x60 |
Maximum Magnification
Beware of telescopes
that are advertised with an “up to 600 magnifications” type of
approach. Any telescope can achieve almost unlimited
magnification (in theory) – it is just that the results will be
less than memorable when the optics are pushed too hard.
The maximum magnification achievable is
only limited by the eyepiece focal length. With a 4mm
eyepiece focal length, our example 200mm f/6 telescope of
1200mm focal length would achieve a magnification of
1200/4 or x300. A 2mm eyepiece focal length would provide
1200/2 or x600, and so on.
But using higher magnifications will not
necessarily show any more detail. This is because we exist at the
bottom of an ocean of air, our atmosphere, which is always
turbulent to some degree. Telescopes not only magnify the image
of distant astronomical objects, they effectively magnify the
atmospheric turbulence as well.
So eyepiece (magnification) choice for
achieving best detail in observing the planets, the Moon or close
binary stars will often be a matter of trial and error. More
often than not you will get the best results with moderate
magnification. Only occasionally, on nights of better “seeing”
will higher powers reveal more detail. On typical nights,
excessive magnification just results in excessive blurring, and
less observable detail.
Resolution
The resolution of a telescope is the
amount of detail theoretically detectable. For point sources of
light (stars), resolution is the angular separation between
two objects which is just at the limit of detectability, where the
two images almost overlap. Note that telescopes cannot form a
point source image of a point object due to a process called
diffraction. Perfect optics actually create a tiny circular
disk-like image surrounded by fainter concentric circles, known as
the Airey Disk).
The theoretical resolution is related
solely to the aperture (D), and the wavelength of the
electromagnetic radiation. In visual wavelengths, the theoretical
resolution of a telescope in seconds of arc is given by :
Resolution = 122 / D
(seconds of arc)
Where D is the aperture in
millimetres.
Note 1 second of arc = 1/60th
of a minute of arc
1 minute of arc = 1/60th
of a degree
So 1 second of arc = 1/3600th
of a degree
The theoretical resolution of the
ASTRONZ range of telescopes at visual wavelengths is as follows:
|
Mirror Diameter
(mm) |
Theoretical Resolution
(seconds of arc) |
|
100 |
1.22 |
|
150 |
0.81 |
|
200 |
0.61 |
|
250 |
0.49 |
|
300 |
0.41 |
In practice, the actual
resolution of a telescope is limited by the “seeing”, or
atmospheric turbulence. In most parts of New Zealand, average
seeing would be 2 seconds of arc (2”) or worse, sometimes much
worse. So on average nights, high aperture telescopes will be
unable to resolve any more detail than those with more modest
apertures.
The best seeing
conditions in the world on Mauna Kea, Cerro Tololo or Sierra
Paranal provide approximately 0.5 second of arc seeing. A view
through the Keck telescopes in Hawaii or one of the VLT’s in Chile
would provide no greater resolution than that of a 250mm aperture
telescope, although you would be able to see fainter objects. It
is to escape the seeing limitations of ground based telescopes
that the Hubble Space Telescope has been so important. Even
though it has only a relatively small 2 metre diameter mirror,
that mirror is able to perform to its theoretical resolution,
unlike the much larger ground based scopes. |